selesaikan barisan geometri U7 =64 U10 = 512 R. = ?
Matematika
angga1093
Pertanyaan
selesaikan barisan geometri
U7 =64
U10 = 512
R. = ?
U7 =64
U10 = 512
R. = ?
1 Jawaban
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1. Jawaban fadlikece
un=a x r/n-1
u7=a x r/7-1
64=a xr/6
64/r/6=a
u10=a x r/10-1
512=64/r/6 x r/9
512/64=r/3
8=r3
2/3=r3
r=2