Di ketahui p=16 q=27 dan r=64, nilai p3/4+q1/3-r5/6 gimana?

16.3/4+27.1/3-64.5/6=
48/4+27/3-320/6=
144/12+108/12-640/12=-388/12

16(3/4) + 27(1/3) - 64(5/6)
(16 : 4 x 3) + (27 : 3 x 1) - (64 x 4 : 6)
12 + 9 - 256/6
21 + 128/3
21/1 + 128/3
63/3 + 128/3
191/3
62[tex] \frac{5}{3} [/tex]