jika p(n) = 3n+8 / n-1,tentukan p(n+1) - p(n)

[tex]p(n)= \frac{3n+8}{n-1} [/tex]
[tex]p(n+1) - p(n) = \frac{3(n+1)+8}{(n+1)-1} - \frac{3n+8}{n-1} [/tex]
[tex] = \frac{3n+11}{n} - \frac{3n+8}{n-1} [/tex]
[tex] = \frac{(3n+11)(n-1)-(3n+8)(n)}{n^2-n}[/tex]
[tex] = \frac{3n^2-3n+11n-11 - 3n^2-8n}{n^2-n} [/tex]
[tex]=-\frac{11}{n^2-n}[/tex]