(^2log 3 + ^4log 9)(^3log 4 + ^9l0g 2)
Matematika
maya1234567898
Pertanyaan
(^2log 3 + ^4log 9)(^3log 4 + ^9l0g 2)
2 Jawaban
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1. Jawaban Anonyme
Bab Logaritma
Matematika SMA Kelas X
^ = pangkat
(²log 3 + ⁴log 9) . (³log 4 + ⁹log 2)
= (²log 3 + ^(2²)log 3²) . (³log 4 + ^(3²)log 2)
= (²log 3 + (2/2) . ²log 3) . (³log 4 + (1/2) . ³log 2)
= (²log 3 + ²log 3) . (³log 4 + ³log √2)
= (2 . ²log 3) . (³log (4√2))
= 2 . ²log (4√2)
= 2 . (²log 4 + ²log √2)
= 2 . (²log 2² + ²log 2^(1/2))
= 2 . (2 + 1/2)
= 2 . 5/2
= 5 -
2. Jawaban lamtiocute
(^2log 3+^2pangkat2 log9)(^3log 2^2 + ^3pangkat2 log 2)
=(^2log 3 x 9^ 1/2) (^3log 2^2 x 2^ 1/2)
=(^2log 3^2)(^3log 2^5/2)
=(2x5/2)(^2log3)(^3log2)
=5