Matematika

Pertanyaan

(^2log 3 + ^4log 9)(^3log 4 + ^9l0g 2)

2 Jawaban

  • Bab Logaritma
    Matematika SMA Kelas X

    ^ = pangkat

    (²log 3 + ⁴log 9) . (³log 4 + ⁹log 2)
    = (²log 3 + ^(2²)log 3²) . (³log 4 + ^(3²)log 2)          
    = (²log 3 + (2/2) . ²log 3) . (³log 4 + (1/2) . ³log 2)
    = (²log 3 + ²log 3) . (³log 4 + ³log √2)
    = (2 . ²log 3) . (³log (4√2))
    = 2 . ²log (4√2)
    = 2 . (²log 4 + ²log √2)
    = 2 . (²log 2² + ²log 2^(1/2))
    = 2 . (2 + 1/2)
    = 2 . 5/2
    = 5
  • (^2log 3+^2pangkat2 log9)(^3log 2^2 + ^3pangkat2 log 2)
    =(^2log 3 x 9^ 1/2) (^3log 2^2 x 2^ 1/2)
    =(^2log 3^2)(^3log 2^5/2)
    =(2x5/2)(^2log3)(^3log2)
    =5

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