Jika g(y)=3y²-7y, tentukan :g(y-1)+g(3y)

Diketahui,
g(y) = 3y^2 - 7y

Maka,
g(y-1) + g(3y)

Tentukan g(y - 1)
g(y) = 3y^2 - 7y
g(y-1) = 3(y-1)^2 - 7(y-1)
g(y-1) = 3y^2 - 3 - 7y + 7
g(y-1) = 3y^2 - 7y + 4

Tentukan g(3y)
g(3y) = 3(3y)^2 - 7(3y)
g(3y) = 3(9y^2) - 21y
g(3y) = 27y^2 - 21y

Maka,
g(y-1) + g(3y) =
(3y^2 - 7y + 4) + (27y^2 - 21y) =
3y^2 + 27y^2 - 7y - 21y + 4 =
30y^2 - 28y + 4

Semoga Membantu,,,,