Matematika

Pertanyaan

penyelesaian persamaan(1/16)pangkat x-2 = 64

2 Jawaban

  • (1/16)^x-2 = 64
    (1/2^4)^x -2 = 2^6
    (2^-4)^x-2 = 2^6
    2^-4x+8 = 2^6
    -4x + 8 = 6
    -4x = 6 - 8
    -4x = - 2
    x = -2/-4
    x = 1/2
  • (1/16)^(x-2) = 64
    (1/(2^4))^(x-2) = 2^6
    (2^(-4))^(x-2) = 2^6
    2^(-4(x-2))= 2^6
    2^(-4x+8) = 2^6

    -4x + 8 = 6
    -4x = 6 - 8
    -4x = -2
    x = -2/-4
    x = 1/2

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