Jika a 2+√3÷2-√3 dan b 2-√3÷2+√3 carilah √a +√b

a = 2+√3÷2-√3
= 2÷2 (√3-√3)
= 1

b = 2-√3÷2+√3
= 2÷2 (-√3+√3)
= 1

√a+√b = 1+1 = 2

a = (2+V3)/(2-V3)
a = [(2+V3)/(2-V3)] × [(2+V3)/(2+V3)]
a = [(2+V3)^2]/(4-3)
a = [(2+V3)^2]/1
a = (2+V3)^2

b = (2-V3)/(2+V3)
b = [(2-V3)/(2+V3)] × [(2-V3)/(2-V3)]
b = [(2-V3)^2]/(4-3)
b = [(2-V3)^2]/1
b = (2-V3)^2

Va + Vb
= V(2+V3)^2 + V(2-V3)^2
= 2+V3 + 2-V3
= 2 + 2 + V3 - V3
= 4