Matematika

Pertanyaan

K(x)=Dx+E. K(2)=1 dan K(5)=10. nilai K(8) adalah

1 Jawaban

  • K(x) = Dx + E

    K(2) = 2D + E
    2D + E = 1

    K(5) = 5D + E
    5D + E = 10

    Eliminasikan
    2D + E = 1
    5D + E = 10
    ------------------ -
    -3D = -9
    D = 3

    2D + E = 1
    2(3) + E = 1
    6 + E = 1
    E = 1 - 6
    E = -5

    rumus fungsi
    K(x) = 3x - 5

    K(8) = 3(8) - 5 = 24 - 5 = 19

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