f(x)= x²+2x+1 tentukan nilai ekstrimnya

Fungsi kuadrat

f(x) = x² + 2x + 1
a = 1 ---> nilai ekstrim = y minimum (ymin)
b = 2

sumbu simetri (x)
x = -b/2a
x = -2/2
x = -1


Nilai ekstrim = ymin = f(-1)
f(-1) = (-1)² + 2(-1) + 1
f(-1) = 0