R1=9 R2=2 R3=5 R4=3 Rtot =15 dihitung R5
Fisika
alfian295
Pertanyaan
R1=9
R2=2
R3=5
R4=3
Rtot =15
dihitung R5
R2=2
R3=5
R4=3
Rtot =15
dihitung R5
1 Jawaban
-
1. Jawaban Monaamaliasaputri
diket. R1= 9 ohm R2 = 2 ohm
R3=5 ohm R4= 3 ohm
Rtot=15 ohm
dit. R5 ?
jawab: cari yg paralel dl
1/Rp=R2+R3+R4
= 1/2+1/5+1/3
=15/30+6/30+10/30
=31/30
Rp=30/31 = 0,967 ohm
sekrang tgl diseri
Rs=R1+Rp+R5
15=9+0,967+R5
R5=15 - 0,967+9
=15 - 9,967
=5,033 ohm