Matematika

Pertanyaan

Luas selimut kerucut 204,1 cm², luas sisi kerucut 282,6 cm², jika phi= 3,14 tentukan volume kerucut

1 Jawaban

  • Lsk = 204,1 cm^2
    Lpk = 282,6 cm^2
    phi = 3,14

    Lpk = La + Lsk
    282,6 = La + 204,1
    La = 282,6 - 204,1
    La = 78,5 cm^2

    La = phi × r^2
    78,5 = 3,14 × r^2
    r^2 = 78,5/3,14
    r^2 = 25
    r = V25
    r = 5 cm

    Lsk = phi × r × s
    204,1 = 3,14 × 5 × s
    204,1 = 15,7 × s
    s = 204,1/15,7
    s = 13 cm

    s^2 = r^2 + t^2
    13^2 = 5^2 + t^2
    169 = 25 + t^2
    t^2 = 169 - 25
    t^2 = 144
    t = V144
    t = 12

    Vt = 1/3 × La × t
    Vt = 1/3 × 78,5 × 12
    Vt = 314 cm^3

    Jadi volume kerucut adalah 314 cm^3

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