Suatu fungsi g(x) = 2x + 1,dengan daerah asal p{1,2,3,4}.daerah hasil fungsi adalah: Please pakai caranya

g(x) = 2x+1
g(1) = 2.1+1
= 2+1
= 3

g(x) = 2x+1
g(2)= 2.2+1
= 4+1
= 5

g(x) = 2x+1
g(3)= 2.3+1
= 6+1
= 7

g(x) = 2x+1
g(4) = 2.4+8
=8+8
=16

berarti daerah hasilnya
Q= {3,5,7,16)
maaf klo salah