Matematika

Pertanyaan

3+9+27+... tentukan A:U6 B:S6

2 Jawaban

  • r = 9/3 = 3


    U6
    = ar^5
    = 3 (3^5)
    = 3^6
    = 729

    S6
    = a (1-r^n) / 1-r
    = 3(1-3^6)/ 1-3
    = 3(-728)/-2
    = 3(364)
    = 1092
  • Materi : Barisan dan Deret
    Kelas : IX SMP

    3 + 9 + 27 + .... + ....

    r = 3
    a = 3

    Un = a.r^(n-1)
    U6 = 3 . 3^(6-1)
    U6 = 3 . 3^5
    U6 = 3^6
    U6 = 729

    Sn = a (1 - r^n ) / 1 - r
    S6 = 3(1 - 3^6) / 1 - 3
    S6 = 3(1 - 729) / -2
    S6 = 3(-728) / -2
    S6 = -2184/-2
    S6 = 1092

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