tentukan fungsi invers h(x) = ³√x+2 tolong pake jalan yaaa

Misalkan h(x) = y
jadi y=3Vx+2
y-2=3Vx
(y-2)^3=x
Jadi
h-1(x)=(x-2)^3

h(x) = [tex]^3\sqrt{x+2}[/tex]
[tex]h(x)^3[/tex] = x + 2
[tex]h(x)^3[/tex] - 2 = x
jd, h'(x) = [tex]x^3[/tex] - 2