Matematika

Pertanyaan

Integral x per akar x +4 dx?

1 Jawaban

  • klo dgn substitusi
    u = (x+4)^1/2
    u^2 = x+ 4
    x = u^2 - 4
    dx/du = 2u
    dx = 2u du

    int x/ (x+4)^1/2 dx = int {(u^2 -4)/u } (2u. du )
    = int 2 (u^2 - 4) du
    = 2 (1/3 u^3 - 4u) + c
    = 2/3 u^3 - 8u
    = 2/3 u( u^2 - 12)
    = 2/3 (u^2 -12) (u)
    = 2/3 (x+4-12) (x+4)^1/2
    = 2/3 (x - 8)(x+4)^1/2

    klo parsial
    int x (x+4)^-1/2 dx
    = 2x (x+4)^(1/2) - 4/3 (x+4)^(3/2)
    = 2/3 (x+4)^(1/2) [ 3x - 2(x+4)]
    = 2/3 (3x-2x-8)(x +4)^1/2
    = 2/3 (x-8)(x + 4)^1/2

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