jika log 2=0,301 dan log3= 0,477 maka ^100log 7,2= tolong dibantu~

LogAritMa

100'log 7,2
= log (72/10) / log 100
= (log 72 - log 10) / log 10²
= (log (2³ . 3²) - 1) / 2
= (3 log 2 + 2 log 3 - 1) / 2
= (3 . 0,301 + 2 . 0,477 - 1) / 2
= (0,903 + 0,954 - 1)/2
= 0,857/2
= 0,4285