Tolong bantu penjabaran binomial newton (2y-1/4y)^5 Terima kasih.

[tex](2y-\frac{1}{4y})^5=(2y)^5-5\cdot(2y)^4\cdot(\frac{1}{4y})+10\cdot(2y)^3\cdot(\frac{1}{4y})^2-10\cdot(2y)^2\cdot(\frac{1}{4y})^3+5\cdot(2y)\cdot(\frac{1}{4y})^4-(\frac{1}{4y})^5=32y^5-20y^3+5y-\frac{5}{8y}+\frac{5}{128y^3}-\frac{1}{1024y^5}[/tex]